Neighbors of the same sign. Given a list of numbers, find and print the first pair of adjacent elements that have the same sign. If no such pair exists, leave the output blank.
|
|
numbers = list(map(int, input().split())) for i in range(1, len(numbers)): if numbers[i] * numbers[i - 1] > 0: print(numbers[i - 1], numbers[i]) break |
Explanation of the Code
- Reading Input:
numbers = list(map(int, input().split()))
- The
input() function reads a line of text from the user.
- The
split() method splits this line into a list of strings based on spaces.
map(int, ...) converts each string in the list to an integer.list(...) converts the map object to a list and stores it in the variable numbers.
- Iterating Through the List and Finding the First Pair with Same Sign:
for i in range(1, len(numbers)):
if numbers[i] * numbers[i - 1] > 0:
print(numbers[i - 1], numbers[i])
break
- Use a
for loop to iterate through the list numbers starting from index 1 to the end of the list.
- In each iteration, check if the product of the current element (
numbers[i]) and the previous element (numbers[i - 1]) is greater than 0.
- If the product is greater than 0, it means both elements have the same sign (both positive or both negative). Print the pair and break the loop.