Reverse the fragment. Given a string in which the letter “h” occurs at least twice, reverse the sequence of characters enclosed between the first and last occurrences of “h”.
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s = input() first_index = s.find('h') last_index = s.rfind('h') reversed_middle = s[first_index + 1:last_index][::-1] print(s[:first_index + 1] + reversed_middle + s[last_index:]) |
Explanation of the Code
- Reading Input:
- The
input() function reads a line of text from the user and stores it in the variable s.
- Finding the First and Last Index of ‘h’:
first_index = s.find('h')
last_index = s.rfind('h')
- The
find('h') method returns the index of the first occurrence of ‘h’.
- The
rfind('h') method returns the index of the last occurrence of ‘h’.
- Reversing the Characters Between the First and Last ‘h’:
reversed_middle = s[first_index + 1:last_index][::-1]
s[first_index + 1:last_index] extracts the substring between the first and last occurrences of ‘h’.- The
[::-1] slice reverses this substring.
- Constructing the Resulting String:
print(s[:first_index + 1] + reversed_middle + s[last_index:])
s[:first_index + 1] gives the substring from the start up to and including the first ‘h’.reversed_middle is the reversed substring between the first and last ‘h’.s[last_index:] gives the substring from the last ‘h’ to the end.- Concatenating these parts constructs the final string.